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Posted

^wtf. das definitely a "thundershock" attack, not "thunderbolt". you can tell by the shade of yellow of the shock -- definitely around the area of 15 amps or so. assuming Pinput = Poutput (and P=IV), i'd expect that approximately 200 watts of power would be produced from the attack, hence, most likely being a "thundershock" (since thundershock power band is approximately 150W - 250W).

Posted

the combo has been broken like twice before right?

Posted

U AIN REAL

u jus a figment of my imagination. U KNO HOW WE FITE OUTSIDE THE BAR?/ YE i was fighting MYSELF. U R MAKEBELIEVE

Posted

desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu desu

Posted
^wtf. das definitely a "thundershock" attack, not "thunderbolt". you can tell by the shade of yellow of the shock -- definitely around the area of 15 amps or so. assuming Pinput = Poutput (and P=IV), i'd expect that approximately 200 watts of power would be produced from the attack, hence, most likely being a "thundershock" (since thundershock power band is approximately 150W - 250W).

Wait, whilst it is true that P=IV, where P = power, I = current and V = voltage, you have only derived the current of flow from the picture itself.

Of course, we have to take into consideration Pikachu's Sp. Atk values, which we cannot derive solely from the picture. However, let us assume that it is a constant value for all populations of Pikachu.

If we assume that your values are corrent, for P = 200 watt, I=15 amps, then:

P=IV

200=15xV

V=200/15

V=13.3.

Therefore, your statement is incorrect/inconclusive and requires further reconsideration.

BOOYAH!

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